Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 1c

Answer

$-0.36$

Work Step by Step

Using operation rules on real numbers, then, \begin{array}{l} -1.2(0.3) \\\\= \dfrac{-12}{10}\cdot\dfrac{3}{10} \\\\= \dfrac{-36}{100} \\\\= -0.36 .\end{array}
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