Answer
$\dfrac{y+x}{x^2y^2}$
Work Step by Step
The expression $
\dfrac{x^{-1}+y^{-1}}{xy}
$ simplifies to
\begin{array}{l}
\dfrac{\dfrac{1}{x}+\dfrac{1}{y}}{xy}
\\\\=
\dfrac{\dfrac{1(y)+1(x)}{xy}}{xy}
\\\\=
\dfrac{\dfrac{y+x}{xy}}{xy}
\\\\=
\dfrac{y+x}{xy}\div xy
\\\\=
\dfrac{y+x}{xy}\cdot\dfrac{1}{xy}
\\\\=
\dfrac{y+x}{x^2y^2}
.\end{array}
