Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 389: 42

Answer

$10.2 \text{ seconds} $

Work Step by Step

Using $D=rt,$ then the conditions of the problem translate to \begin{array}{l}\require{cancel} 300=\dfrac{88}{3}t .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} \dfrac{3}{88}(300)=\left(\dfrac{88}{3}t\right)\dfrac{3}{88} \\\\ \dfrac{900}{88}=t \\\\ t=10.227272727272727272727272727273 .\end{array} To the nearest tenth, it would take $ 10.2 \text{ seconds} $ for the snake to travel.
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