Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 387: 19

Answer

$1,1$ and $5,\dfrac{1}{5}$

Work Step by Step

Let $x$ be the number. Then its reciprocal is $\dfrac{1}{x}.$ The conditions of the problem translate to the equation \begin{array}{l}\require{cancel} x+5\cdot\dfrac{1}{x}=6 .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} x+\dfrac{5}{x}=6 \\\\ x\left( x+\dfrac{5}{x} \right) =(6)x \\\\ x^2+5=6x \\\\ x^2-6x+5=0 \\\\ (x-5)(x-1)=0 .\end{array} Equating each factor to zero and then solving for the variable, the solutions of the equation above are $ x=\left\{ 1,5 \right\} .$ Hence the numbers are the pairs $ 1,1$ and $5,\dfrac{1}{5}.$
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