Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 387: 17

Answer

$c=\dfrac{2Lw}{\theta}$

Work Step by Step

Using the properties of equality, in terms of $ c ,$ the given equation, $ \dfrac{\theta}{w}=\dfrac{2L}{c} ,$ is equivalent to \begin{array}{l} \theta c=2Lw \\\\ c=\dfrac{2Lw}{\theta} .\end{array}
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