Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 387: 14

Answer

$r=\dfrac{E-IR}{I}$

Work Step by Step

Using the properties of equality, in terms of $ r ,$ the given equation, $ I=\dfrac{E}{R+r} ,$ is equivalent to \begin{array}{l} I(R+r)=E \\\\ IR+Ir=E \\\\ Ir=E-IR \\\\ r=\dfrac{E-IR}{I} .\end{array}
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