Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 387: 8

Answer

$n=\dfrac{2S-nL}{a}$

Work Step by Step

Using the properties of equality, in terms of $ a ,$ the given equation, $ S=\dfrac{n(a+L)}{2} ,$ is equivalent to \begin{array}{l} 2S=n(a+L) \\\\ 2S=na+nL \\\\ 2S-nL=na \\\\ \dfrac{2S-nL}{a}=n \\\\ n=\dfrac{2S-nL}{a} .\end{array}
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