Answer
$$\frac{-y^{40}}{z^5}$$
Work Step by Step
We have $$(\frac{-xy^{-5}z}{xy^3})^{-5}$$
Simplifying $$(\frac{-z}{y^5y^3})^{-5}$$ $$(\frac{-z}{y^8})^{-5}$$ $$(\frac{-y^8}{z})^{5}$$
$$\frac{-y^{40}}{z^5}$$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Test - Page 332: 4
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