Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 24

Answer

$$(y-3)(x-3)(x+3)$$

Work Step by Step

We have $$x^2y-9y-3x^2+27$$ Factorizing $$y(x^2-9) -3(x^2-9)$$ $$(y-3)(x^2-9)$$ $$(y-3)(x-3)(x+3)$$
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