Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 11

Answer

$$12x^2-5x-28$$

Work Step by Step

We have $$(3x+4)(4x-7)$$ Multiplicating $$12x^2-21x+16x-28$$ $$12x^2-5x-28$$
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