Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 2

Answer

$-12x^{2}z $

Work Step by Step

Using the laws of exponents, the given expression, $ -3xy^{-2}(4xy^2)z $, simplifies to \begin{array}{l} (-3)(4)x^{1+1}y^{-2+2}z \\\\= -12x^{2}y^{0}z \\\\= -12x^{2}z .\end{array}
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