Answer
$$\frac{3a^7}{2b^5}$$
Work Step by Step
We have $$\frac{6^{-1}a^2b^{-3}}{3^{-2}a^{-5}b^2}$$
Simplifying $$\frac{3^2a^2*a^5}{6b^2*b^3}$$ $$\frac{9a^7}{6b^5}=\frac{3a^7}{2b^5}$$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Test - Page 332: 3
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