Answer
For both forms, $h(1)=48$.
Work Step by Step
Find $h(1)$ by substituting 1 to $t$ in the original expression to have:
$h(1) = -16(1^2)+64(1)
\\h(1)=-16(1)+64
\\h(1)=-16+64
\\h(1)=48$
Find $h(1)$ using the factored form of $h(t)$ to have:
$\\h(t) = -16t(t-4)
\\h(1)=-16(1) (1-4)
\\h(1)=-16(-3)
\\h(1)=48$
