Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 296: 101

$f(x)=3\left( 67x^3-839x^2+2325x+27878 \right)$

Factoring the $GCF=3,$ the given function, $ f(x)=201x^3-2517x^2+6975x+83634 ,$ is equivalent to \begin{array}{l}\require{cancel} f(x)=3\left( \dfrac{201x^3}{3}-\dfrac{2517x^2}{3}+\dfrac{6975x}{3}+\dfrac{83634}{3} \right) \\ f(x)=3\left( 67x^3-839x^2+2325x+27878 \right) .\end{array}