Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 296: 100a

$h(t)=-16\left( t^2-14 \right)$

Factoring the negative $GCF=-16,$ the given function, $ h(t)=-16t^2+224 ,$ is equivalent to \begin{array}{l}\require{cancel} h(t)=-16\left( \dfrac{-16t^2}{-16}+\dfrac{224}{-16} \right) \\ h(t)=-16\left( t^2-14 \right) .\end{array}