Answer
For both expressions, $h(2)=160$.
Work Step by Step
Find $h(1)$ by substituting 1 to t in the original expression to have:
$h(2)=-16(2^2)+224
\\h(2)=-16(4)+224
\\h(2)=-64+224
\\h(2)=160$
Find $h(2)$ using the factored form of $h(t)$ to have:
$h(t)=-16(t^2-14)
\\h(2)=-16(2^2-14)
\\h(2)=-16(4-14)
\\h(2)=-16(-10)
\\h(2)=160$
