Answer
Without 1 in the factored form, the result does not equal that of the given polynomial.
Work Step by Step
$3x^{2}−9x+3$ factored is $3(x^{2}−x+1)$.
Without $1$, we get $3x^{2}−9x$.
$3(x^{2}−x)=3x^{2}−9x$
Because there is no $1$, we cannot distribute the $3$ to a third term, which leaves out an essential part of the polynomial.
