Answer
$(1,4)$
Work Step by Step
$y=3x^{2}+5x-4$ Equation $(1)$
$y=3x^{2}-x+2$ Equation $(2)$
From Equation $(1)$ and Equation $(2)$
$3x^{2}+5x-4 = 3x^{2}-x+2$
$3x^{2}+5x-4 - 3x^{2}+x-2=0$
$6x-6=0$
$6(x-1)=0$
$x=1$
Substitute $x$ value in Equation $(1)$
$y=3x^{2}+5x-4$
$y=3(1)^{2}+5(1)-4$
$y=3+5-4$
$y=8-4$
$y=4$
$(1,4)$ satisfies both the equations. So solution is $(1,4)$
