Answer
(2,4) and (-1,1)
Work Step by Step
$y=x+2$, and $y=x^2$, which means $x+2=x^2$
Rearrange the equation:
$x^2-x-2=0$
Factor:
$(x-2)(x+1)=0$
The two solutions for $x$ are $x=2$, and $x=-1$
Use the first equation, $y=x+2$, to solve for y.
When $x=2$:
$y=2+2=4$
When $x=-1$:
$y=2+(-1)=2-1=1$
Therefore the solutions are (2,4) and (-1,1).
