Answer
$\left( x-5 \right)^2+y^2=25$
Work Step by Step
Using the standard form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2$ where the center is $(h,k)$ and radius $r$, then the equation of the circle with the given center at $
(5,0)
$ and the given radius is $
5
$ is
\begin{array}{l}
\left( x-5 \right)^2+\left( y-0 \right)^2=5^2\\\\
\left( x-5 \right)^2+y^2=25
.\end{array}
