Answer
multiple answers; see details
Work Step by Step
The standard form of the equation $
x^2+y^2-3y=\dfrac{7}{4}
$ is
\begin{array}{l}
x^2+\left(y^2-3y+\dfrac{9}{4}\right)=\dfrac{7}{4}+\dfrac{9}{4}\\\\
x^2+\left(y-\dfrac{3}{2}\right)^2=4
.\end{array}
The graph of this equation is a $\text{
circle
}$ with the following properties:
\begin{array}{l}
\text{Center: }\left(
0,\dfrac{3}{2}
\right),\\\\\text{Radius: }
2
.\end{array}
Using the properties above, the graph of the equation is given below.
