Answer
$S_{32}=-1200$
Work Step by Step
The first n term of an arithmetic sequence can be calculated as:
$S_n=\frac{n}{2}(a_1+a_n)$
We have to find the 32nd term first:
$a_{n}=a_1+d\times(n-1)$
$a_{32}=9+(-3)\times(32-1)=9-93=-84$
Therefore we can substitute in the formula of the sum, and we get:
$S_{32}=\frac{32}{2}\times(9-84)=16\times-75=-1200$