Answer
$a_1=2$
$d=2$
Work Step by Step
We have an arithmetic sequence in which $a_{12}=24$ and $a_{25}=50.$ In order to find $a_{1}$ and $d$ we will use the fact that any term of arithmetic sequence is expressed through the formula $a_{n}=a_1+d(n-1)$
Hence,
$a_{12}=a_1+d\cdot11$
$a_{25}=a_1+d\cdot24$
$a_{25}-a_{12}=a_1+d\cdot24-a_1-d\cdot11=d(24-11)=13d$
$50-24=13d$
So $d=2$
Nowe we can use any equation to find $a_1.$
$24=a_1+2\cdot11$
$a_1=2$