Answer
$a_1=1$
$d=1$
Work Step by Step
We have an arithmetic sequence in which $a_{13}=13$ and $a_{54}=54.$ In order to find $a_{1}$ and $d$ we will use the fact that any term of arithmetic sequence is expressed through the formula $a_{n}=a_1+d(n-1)$
Hence,
$a_{13}=a_1+d\cdot12$
$a_{54}=a_1+d\cdot53$
$a_{54}-a_{13}=a_1+d\cdot53-a_1-d\cdot12=d(53-12)=41d$
$54-13=41d$
So $d=1$
Nowe we can use any equation to find $a_1.$
$13=a_1+1\cdot12$
$a_1=1$