Answer
Equation of a circle with center $\left( 3,0 \right)$ and radius $5$ is ${{\left( x-3 \right)}^{2}}+{{\left( y \right)}^{2}}=25$
Work Step by Step
First, we use the mid-point formula to find the center of the circle.
$\begin{align}
& \left( \frac{7+\left( -1 \right)}{2},\frac{3+\left( -3 \right)}{2} \right) \\
& \left( \frac{6}{2},\frac{0}{2} \right) \\
\end{align}$
Center of circle $\left( 3,0 \right)$.
The radius is the distance between end point and center $\left( 7,3 \right)$ and $\left( 3,0 \right)$.
