Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Study Summary - Practice Exercises - Page 844: 61

Answer

The value of x is 0.0498.

Work Step by Step

Consider the logarithmic equation. $2\ln x=-6$ Simplify the logarithm $2\ln x=-6$ as follows. $\begin{align} & 2\ln x=-6 \\ & \ln x=-3 \end{align}$ Use the fact that the expression ${{\log }_{a}}x=m\text{ is equivalent to }{{a}^{m}}=x$. Therefore, $\begin{align} & x={{e}^{-3}} \\ & \approx 0.0498 \end{align}$ Check: Substitute $x=0.0498$ in the given equation. $\begin{matrix} 2\ln \left( 0.0498 \right)\overset{?}{\mathop{=}}\,-6 \\ \text{ }2\left( -3 \right)\overset{?}{\mathop{=}}\,-6 \\ \text{ }-6=-6 \\ \end{matrix}$ Thus, the obtained solution is correct.
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