Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Study Summary - Practice Exercises - Page 844: 59

Answer

The value of x is 3.5850.

Work Step by Step

Consider the exponential equation. ${{2}^{x}}=12$ $x={{\log }_{2}}12$ Use the base change formula and solve. $x=\frac{\log 12}{\log 2}$ Use a calculator and solve. $\begin{align} & x\approx \frac{1.079}{0.3010} \\ & =3.5847 \end{align}$ Check: Substitute $x=3.5847$ in the given equation. $\begin{matrix} {{2}^{3.5847}}\overset{?}{\mathop{=}}\,12 \\ \text{ }11.99\overset{?}{\mathop{=}}\,12 \\ \text{ }12\approx 12 \\ \end{matrix}$ Thus, the obtained solution is correct.
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