Answer
True.
Work Step by Step
$\log_{a}(Q+Q^{2})=\qquad$ ... rewrite $Q+Q^{2}$ as $Q(1+Q)$
$=\log_{a}[Q(1+Q)]\qquad$ ... apply $\log_{a}(MN)=\log_{a}M+\log_{a}N$
$=\log_{a}Q+\log_{a}(Q+1)$
True.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 12 - Exponential Functions and Logarithmic Functions - 12.4 Properties of Logarithmic Functions - 12.4 Exercise Set - Page 811: 93
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