Answer
$f\left( x \right)={{x}^{2}}-9x+14$, the $y$-intercept is $\left( 0,f\left( 0 \right) \right)\text{ or }\underline{\left( \text{0,14} \right)}$ and the $x-$intercepts are $\underline{\left( 2,0 \right)}\text{ and }\underline{\left( 7,0 \right)}$
Work Step by Step
The $y$-intercept is $\left( 0,f\left( 0 \right) \right)\text{ or }\left( \text{0,14} \right)$
To find the $x$-intercept, solve the equation, $y=0\text{ or }f\left( x \right)={{x}^{2}}-9x+14=0$
Rewrite the above equation and factor.
$\begin{align}
& {{x}^{2}}-7x-2x+14=0 \\
& x\left( x-7 \right)-2\left( x-7 \right)=0 \\
& \left( x-2 \right)\left( x-7 \right)=0 \\
& x-2=0\text{ or }x-7=0
\end{align}$
Therefore the $x-$intercepts are $\left( 2,0 \right)\text{ and }\left( 7,0 \right)$
