Answer
$3x^{3}-7x^{2}-2x+8$
Work Step by Step
To find the product of $(x-2)$ and $(3x^{2}-x-4)$, we need to use the distributive property in which each term of the first polynomial is multiplied to each term of the second polynomial. Then, we simplify the resultant expression:
$(x-2)(3x^{2}-x-4)$
=$x(3x^{2}-x-4)-2(3x^{2}-x-4)$
=$3x^{3}-x^{2}-4x-6x^{2}+2x+8$
=$3x^{3}-x^{2}-6x^{2}-4x+2x+8$
=$3x^{3}-7x^{2}-2x+8$
