Answer
$\frac{7}{4}$
Work Step by Step
$2^{0}$ + $2^{-1}$ + $2^{-2}$ =
Recall: $a^{-b}$ = $\frac{1^{b}}{a^{b}}$
So, we have:
$2^{0}$ + $\frac{1^{1}}{2^{1}}$ + $\frac{1^{2}}{2^{2}}$ =
1 + $\frac{1}{2}$ + $\frac{1}{4}$ =
Make all of the denominators equal.
$\frac{4}{4}$ $\times$ 1 + $\frac{2}{2}$ $\times$ $\frac{1}{2}$ + $\frac{1}{4}$ =
$\frac{4}{4}$ + $\frac{2}{4}$ + $\frac{1}{4}$ =
$\frac{7}{4}$
