Answer
$0$
Work Step by Step
$\frac{2x+3y}{x-y}$
$x=\frac{1}{2}$
$y=-\frac{1}{3}$
$\frac{2(\frac{1}{2})+3(-\frac{1}{3})}{(\frac{1}{2})-(-\frac{1}{3})}=\frac{1-1}{\frac{3}{6}+\frac{2}{6}}=0$
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