Answer
-1
Work Step by Step
We will evaluate the expression by first simplifying the expression and then substituting $x=-1$ into the resultant expression:
$(x^{2}+2x-4)-(x^{2}-x-2)+(2x^{2}-3x-1)$
=$x^{2}+2x-4-x^{2}+x+2+2x^{2}-3x-1$
=$x^{2}-x^{2}+2x^{2}+2x+x-3x-1-4+2$
=$2x^{2}+3x-3x-5+2$
=$2x^{2}+0-3$
=$2x^{2}-3$
=$2(-1)^{2}-3$
=$2(1)-3$
=$2-3$
=$-1$
