Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set - Page 186: 8

$-\dfrac{1}{10}n$

Using the $LCD= 30 ,$ the given expression, $ \dfrac{1}{3}n-\dfrac{4}{15}n+\dfrac{5}{6}n-n ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{10}{30}n-\dfrac{8}{30}n+\dfrac{25}{30}n-\dfrac{30}{30}n \\\\= \left( \dfrac{10-8+25-30}{30}\right)n \\\\= \dfrac{-3}{30}n \\\\= -\dfrac{1}{10}n .\end{array}