Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set - Page 186: 7

$\dfrac{1}{4}x$

Using the $LCD= 12 ,$ the given expression, $ \dfrac{1}{2}x-\dfrac{3}{4}x+\dfrac{2}{3}x-\dfrac{1}{6}x ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{6}{12}x-\dfrac{9}{12}x+\dfrac{8}{12}x-\dfrac{2}{12}x \\\\= \left( \dfrac{6-9+8-2}{12}\right)x \\\\= \dfrac{3}{12}x \\\\= \dfrac{1}{4}x .\end{array}