Answer
{$\frac{1}{2},\frac{3}{4}$}
Work Step by Step
Using the rules for factoring trinomials, we obtain:
$8x^{2}-10x+3=0$
$8x^{2}-4x-6x+3=0$
$4x(2x-1)-3(2x-1)=0$
$(2x-1)(4x-3)=0$
$(2x-1)=0$ or $(4x-3)=0$
$2x=1$ or $4x=3$
$x=\frac{1}{2}$ or $x=\frac{3}{4}$
Therefore, the solution set is {$\frac{1}{2},\frac{3}{4}$}.
