Answer
{$-3,\frac{5}{3}$}
Work Step by Step
Using Property 10.1, which says that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
Step 1: $(3x+2)^{2}=49$
Step 2: $3x+2=\pm \sqrt {49}$
Step 3: $3x+2=\pm 7$
Step 4: $3x+2=7$ or $3x+2=-7$
Step 5: $3x=7-2$ or $3x=-7-2$
Step 6: $3x=5$ or $3x=-9$
Step 7: $x=\frac{5}{3}$ or $x=-3$
The solution set is {$-3,\frac{5}{3}$}.
