Answer
$x = \frac{3±\sqrt {41}}{4}$
Work Step by Step
This equation is not easily factorable, so we use the quadratic formula, where the current equation is in the form $0=ax^{2}+bx+c$. Thus, we obtain:
$2x^{2} - 3x - 4 = 0$
$x = \frac{-b±\sqrt {b^{2}-4ac}}{2a}$
$x = \frac{-(-3)±\sqrt {(-3)^{2}-4(2)(-4)}}{2(2)}$
$x = \frac{3±\sqrt {9+32}}{4}$
$x = \frac{3±\sqrt {41}}{4}$
