Answer
No real number solutions
Work Step by Step
We will solve the equation using the property that says that if $x^{2}=a$, then $x=\pm\sqrt a$:
Step 1: $(2x-1)^{2}=-16$
Step 2: $2x-1=\pm \sqrt {-16}$
As $\sqrt {-16}$ cannot be solved without introducing complex numbers, there are no real number solutions to the equation.
