Answer
{$-12,2$}
Work Step by Step
Using the rules for factoring trinomials, we obtain:
$y^{2}+10y=24$
$y^{2}+10y-24=0$
$y^{2}-2y+12y-24=0$
$y(y-2)+12(y-2)=0$
$(y-2)(y+12)=0$
$(y-2)=0$ or $(y+12)=0$
$y=2$ or $y=-12$
Therefore, the solution set is {$-12,2$}.