Answer
{$\frac{1}{3}$}
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$9x^{2}-6x+1=0$
$9x^{2}-3x-3x+1=0$
$3x(3x-1)-1(3x-1)=0$
$(3x-1)(3x-1)=0$
$(3x-1)=0$ or $(3x-1)=0$
$x=\frac{1}{3}$ or $x=\frac{1}{3}$
Therefore, the solution set is {$\frac{1}{3}$}.
