Answer
{$-1,\frac{7}{5}$}.
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$5x^{2}-2x-7=0$
$5x^{2}+5x-7x-7=0$
$5x(x+1)-7(x+1)=0$
$(x+1)(5x-7)=0$
$(x+1)=0$ 0r $(5x-7)=0$
$x=-1$ or $x=\frac{7}{5}$
Therefore, the solution set is {$-1,\frac{7}{5}$}.
