Answer
{$-3,1$}
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$t^{2}+2t-3=0$
$t^{2}-1t+3t-3=0$
$t(t-1)+3(t-1)=0$
$(t-1)(t+3)=0$
$(t-1)=0$ or $(t+3)=0$
$t=1$ or $t=-3$
Therefore, the solution set is {$-3,1$}.
