Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 457: 5

{$-1,2$}

Factoring the equation and setting the factors equal to zero, we obtain: $t^{2}-t-2=0$ $t^{2}+1t-2t-2=0$ $t(t+1)-2(t+1)=0$ $(t+1)(t-2)=0$ $(t+1)=0$ or $(t-2)=0$ $t=-1$ or $t=2$ Therefore, the solution set is {$-1,2$}.