Answer
{$-\frac{4}{3},2$}
Work Step by Step
Using Property 10.1, which says that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
Step 1: $(3n-1)^{2}=25$
Step 2: $3n-1=\pm \sqrt {25}$
Step 3: $3n-1=\pm 5$
Step 4: $3n-1=5$ or $3n-1=-5$
Step 5: $3n=5+1$ or $3n=-5+1$
Step 6: $3n=6$ or $3n=-4$
Step 7: $n=\frac{6}{3}=2$ or $n=-\frac{4}{3}$
The solution set is {$-\frac{4}{3},2$}.
