Answer
$-5,2$ and $-2$
Work Step by Step
The given function is
$\Rightarrow f(x)=(x+5)(x^2-4)$
Substitute $0$ for $f(x)$.
$\Rightarrow 0=(x+5)(x^2-4)$
$\Rightarrow 0=(x+5)(x^2-2^2)$
Use difference of two squares pattern.
$\Rightarrow 0=(x+5)(x-2)(x+2)$
Use zero product property.
$\Rightarrow x+5=0$ or $x-2=0$ or $x+2=0$
Solve for $x$.
$\Rightarrow x=-5$ or $x=2$ or $x=-2$
Hence, the zeros of the function are $-5,2$ and $-2$.
