Chapter 8 - Graphing Quadratic Functions - 8.5 - Using Intercept Form - Exercises - Page 455: 21

$2$ and $10$

The given function is $\Rightarrow y=-2(x-2)(x-10)$ Substitute $0$ for $f(x)$. $\Rightarrow 0=-2(x-2)(x-10)$ Use zero product property. $\Rightarrow x-2=0$ or $x-10=0$ Solve for $x$. $\Rightarrow x=2$ or $x=10$ Hence, the zeros of the function are $2$ and $10$.