Answer
$13$ and $4$
Work Step by Step
The given function is
$\Rightarrow y=x^2-17x+52$
Substitute $0$ for $y$.
$\Rightarrow 0=x^2-17x+52$
Factor the trinomial.
$\Rightarrow 0=(x-13)(x-4)$
Use zero product property.
$\Rightarrow x-13=0$ or $x-4=0$
Solve for $x$.
$\Rightarrow x=13$ or $x=4$
Hence, the zeros of the function are $13$ and $4$.
