Answer
$-5$ and $1$
Work Step by Step
The given function is
$\Rightarrow f(x)=\frac{1}{3}(x+5)(x-1)$
Substitute $0$ for $f(x)$.
$\Rightarrow 0=\frac{1}{3}(x+5)(x-1)$
Use zero product property.
$\Rightarrow x+5=0$ or $x-1=0$
Solve for $x$.
$\Rightarrow x=-5$ or $x=1$
Hence, the zeros of the function are $-5$ and $1$.
