Answer
$-(x+1)(3x-2)$.
Work Step by Step
The given polynomial is
$=-3x^2-x+2$
Rewrite $-x$ as $-3x+2x$.
$=-3x^2-3x+2x+2$
Group the terms.
$=(-3x^2-3x)+(2x+2)$
Factor each group.
$=-3x(x+1)+2(x+1)$
Factor out $(x+1)$.
$=(x+1)(-3x+2)$
$=-(x+1)(3x-2)$
Hence, the factor of the polynomial is $-(x+1)(3x-2)$.
